526-x^2=0

Solution for 526-x^2=0 equation:

526-x^2=0

We add all the numbers together, and all the variables

-1x^2+526=0

a = -1; b = 0; c = +526;
Δ = b2-4ac
Δ = 02-4·(-1)·526
Δ = 2104
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2104}=\sqrt{4*526}=\sqrt{4}*\sqrt{526}=2\sqrt{526}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{526}}{2*-1}=\frac{0-2\sqrt{526}}{-2}
=-\frac{2\sqrt{526}}{-2}
=-\frac{\sqrt{526}}{-1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{526}}{2*-1}=\frac{0+2\sqrt{526}}{-2}
=\frac{2\sqrt{526}}{-2}
=\frac{\sqrt{526}}{-1}
$